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OK BOZ SENTHIL KUMAR C

OK BOZ
SENTHIL KUMAR C

OK BOZ is a WORD Trademark filed on Feb 24, 2021 in TAMIL NADU through India IP Office.The Trademark is registered to SENTHIL KUMAR C and was filed by SNEHA MANJOORAN[32262].

OK BOZ SENTHIL KUMAR C Trademark Information

Application ID

4878506

Status

Registered

Date of Application

Feb 24, 2021

Classes

Proprietor(s)

SENTHIL KUMAR C

Attorney

SNEHA MANJOORAN[32262]
F-97, 4th Floor, Anna Nagar (East), Chennai - 600102, Tamil Nadu.

Type

WORD

Registration State

TAMIL NADU

Country

India

Published

Mar 22, 2021

Filing Mode

e-Filing

IP Office

CHENNAI

Used Since

06/07/2019

Valid/Upto

24/02/2031

Uploaded Documents

TM-A(TRADE MARKS APPLICATION)

Feb 24, 2021

Journal Copy

Mar 26, 2021

Certificate

Aug 03, 2021

FAQ's for OK BOZ SENTHIL KUMAR C Trademark

The application for OK BOZ was made on Feb 24, 2021

The trademark applicant for OK BOZ is SENTHIL KUMAR C.

Trademark application has been filed under the class(es) 39.

As per IP India, trademark application is on the following stage: Registered.

Listed application Id of OK BOZ is 4878506.

Trademark attorney of the OK BOZ is SNEHA MANJOORAN[32262].

OK BOZ Trademark is a WORD mark.

Disclaimer: Vakilsearch assumes no responsibility or liability for any errors or omissions in the content of this page. The data is derived from mca.gov.in and ipindia.gov.in